I made the assumption that your avg thickness wouldn't change. Say your avg thickness is 2 in. Using the square and the rectangle in the previous post, the volumes would be 50 cubic inches and 32...
Type: Posts; User: silas; Keyword(s):
I made the assumption that your avg thickness wouldn't change. Say your avg thickness is 2 in. Using the square and the rectangle in the previous post, the volumes would be 50 cubic inches and 32...
Constant perimeter (the string) doesn't make for a constant area. If the string is 20 inches long you could make it into a a 5 in by 5 in square with an area of 25 square inches. You could also...
